howardb
Expert Member
- Joined
- Sep 12, 2003
- Messages
- 3,647
Hi all,
Been doing a lot of reading this past weekend on the subject, but cannot get a definitive working of how I should do this. Any comments/suggestions/guidelines would be welcome.
I need to string 6 LED's approx. 30-40cm apart - the LEDs are different colours (Blue, Green and Red). When I purchased them, the seller reflected the following specs for each:
Blue/Green = 3v-3.5v, 350mA, 1W, 8mm epistar
Red = 2v-2.4v, 350mA, 1W, 8mm epistar
I have tested each LED and confirm I'm happy to run the lower voltages of 3v and 2v.
To keep the wiring as simple as possible, I'm wanting to use 2-core for the string, parallel LED connections to +/-.
Now the power supply being used was to be a 12v constant (10A max output; can adjust the PSU output to 10V if needed), however I then decided to maybe step 12v down to 3v using a LM2596S DC-DC Step Down CC-CV Adjustable Power Supply Module - I thought it may save me having to possibly fiddle with resistors on all LEDs, etc.
My question is:
I want to string these LEDs in this sequence - Blue, Red Green, Blue Red, Green - if I connect them in parallel from the 3V supply (seems easier than series/parallel on 12v), the Blue and Green would run fine on the 3v, but the Red would burn out as it's 2v rated. According to the different online calcs, I should be using a 3.3ohm resistor on the Red LEDs.
3v+ ___ Blue+ ___3.3ohm/Red+_____Green+__repeat
3v- ___ Blue- ___Red-____________Green-__repeat
Based on R= V1-V2/I
R= 3v-2v/0.35a = 2.8ohm (3.3ohm resistor is the closest for the Red LEDs)
To me, the 3.3ohm seems too little due to the 350mA rating? Should the mA of all 6 LED's be calculated instead, i.e. 3v-2v/2.1a = 0.5ohm? Also seems incorrect...
If it's easier to run directly off the 12v, I'd appreciate some input, guidelines.
To be honest, the resistance is the confusion for me, given I want to connect in parallel... maybe I'm just not grasping the formulas...
Been doing a lot of reading this past weekend on the subject, but cannot get a definitive working of how I should do this. Any comments/suggestions/guidelines would be welcome.
I need to string 6 LED's approx. 30-40cm apart - the LEDs are different colours (Blue, Green and Red). When I purchased them, the seller reflected the following specs for each:
Blue/Green = 3v-3.5v, 350mA, 1W, 8mm epistar
Red = 2v-2.4v, 350mA, 1W, 8mm epistar
I have tested each LED and confirm I'm happy to run the lower voltages of 3v and 2v.
To keep the wiring as simple as possible, I'm wanting to use 2-core for the string, parallel LED connections to +/-.
Now the power supply being used was to be a 12v constant (10A max output; can adjust the PSU output to 10V if needed), however I then decided to maybe step 12v down to 3v using a LM2596S DC-DC Step Down CC-CV Adjustable Power Supply Module - I thought it may save me having to possibly fiddle with resistors on all LEDs, etc.
My question is:
I want to string these LEDs in this sequence - Blue, Red Green, Blue Red, Green - if I connect them in parallel from the 3V supply (seems easier than series/parallel on 12v), the Blue and Green would run fine on the 3v, but the Red would burn out as it's 2v rated. According to the different online calcs, I should be using a 3.3ohm resistor on the Red LEDs.
3v+ ___ Blue+ ___3.3ohm/Red+_____Green+__repeat
3v- ___ Blue- ___Red-____________Green-__repeat
Based on R= V1-V2/I
R= 3v-2v/0.35a = 2.8ohm (3.3ohm resistor is the closest for the Red LEDs)
To me, the 3.3ohm seems too little due to the 350mA rating? Should the mA of all 6 LED's be calculated instead, i.e. 3v-2v/2.1a = 0.5ohm? Also seems incorrect...
If it's easier to run directly off the 12v, I'd appreciate some input, guidelines.
To be honest, the resistance is the confusion for me, given I want to connect in parallel... maybe I'm just not grasping the formulas...
Last edited: