About a year ago, I replaced the battery (3.5Ah/24V) on my garage door (Digidoor One). I wasn't paying attention, plugged the cable in the wrong way around, and blew a resistor on the board.
Since then, the board couldn't charge the battery and after a couple of months that battery was destroyed.
I recently checked out a neighbour's working Digidoor One and was able to determine that the resistor I need to replace is 20 Ohm (5 watt). I visited three shops today (Yebo Electronics, Cape Town Components and Mantech). None had a 20 Ohm resistor, so I settled for a 22 Ohm (5 watt) resistor.
I soldered it in place this afternoon and the multimeter reports 36V on the cable that connects to the battery. This seemed high to charge a 24V battery, so I checked the voltage on the neighbour's garage door and measured 30V.
Questions:
I basically need to know if I can plug my 2x12V batteries in to be charged by 36V, or should I instead continue the search for the correct resistor in order to charge at 30V, assuming the the 6V difference is indeed caused by the 22 ohm resistor.
I'd appreciate any input from knowledgable members.
Since then, the board couldn't charge the battery and after a couple of months that battery was destroyed.
I recently checked out a neighbour's working Digidoor One and was able to determine that the resistor I need to replace is 20 Ohm (5 watt). I visited three shops today (Yebo Electronics, Cape Town Components and Mantech). None had a 20 Ohm resistor, so I settled for a 22 Ohm (5 watt) resistor.
I soldered it in place this afternoon and the multimeter reports 36V on the cable that connects to the battery. This seemed high to charge a 24V battery, so I checked the voltage on the neighbour's garage door and measured 30V.
Questions:
- Can the 6V difference as measured be explained by the 2 ohm difference between the resistors?
- I have not yet connected the terminal to the new batteries, as I don't want to damage the new batteries. What is the risk?
I basically need to know if I can plug my 2x12V batteries in to be charged by 36V, or should I instead continue the search for the correct resistor in order to charge at 30V, assuming the the 6V difference is indeed caused by the 22 ohm resistor.
I'd appreciate any input from knowledgable members.
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