Need help!Job requiring math test

ViciousClone

Expert Member
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Apr 26, 2012
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4,205
Hi,i know im not in the right place posting this but i couldn't find another place.

I have a 2nd interview tomorrow and they told me to just prep up for a normal algebra sum.

This isn't helping me much as algebra covers a big area and haven't used it YEARS!

They said its just to see how i work it out.

Any idea what kind of sum they will give me?

as well i should be getting an excel test as well?

Please assist ,thanks!
 

Johnatan56

Honorary Master
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Aug 23, 2013
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30,957
Are you talking about something like

2x + 4y = 8
3x - y = 5

or how to use formulas. Just go open a grade 6/7 maths book.
 

ViciousClone

Expert Member
Joined
Apr 26, 2012
Messages
4,205
Are you talking about something like

2x + 4y = 8
3x - y = 5

or how to use formulas. Just go open a grade 6/7 maths book.
Well thats what im thinking when someone mentions algebra ..

He did say its not a rocket science sum and is a basic algebra sum..
 

Mortymoose

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May 26, 2013
Messages
13,287
is x = 2 then and y = 1?

out of curiosity, seeing as I last looked at this stuff in 1988....

:confused:
 

Johnatan56

Honorary Master
Joined
Aug 23, 2013
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30,957
So for my post:
2x + 4y = 8 ....1 (Note I add the .... 1 and circle the number in order for one to know which equation I am working with)
3x - y = 5 ....2

You need to have x or y "equal":
(The 2 would be circled, so you know I am working on equation 2)
2 x 4: 12x - 4y = 20 ....3

So now the y's are equal. We can add 3 and 1 together so that they cancel each other out (we could also subtracts them from each other in any order, 3-1, 1-3 etc.)
3 + 1: 12x + 2x - 4y + 4x = 20 + 8
------- 14x = 28
/2: --- x = 2

Now substitute x = 2 into 1 or 2 (you want to avoid substituting it into 3, you can but in case of a mistake it may not show up).
2 (2) + 4y = 8
4 + 4y = 8
4y = 8 - 4
4y = 4
y = 1

therefore x =2 and y = 1. You can make this more complex with more variables, e.g. x, y and z. Then you will need 3 equations, same steps overall. Get 2 equations of the 3 that only have x/y or y/z or x/z. Then proceed like above.
All my ....number etc. is just notation, you don't need to do it.

Try these:

4x + 30y = 320
100x + 50y = 1000

and
-5y + 3x + y - 8 = 42
-35 + 2x + 1/3 x + 2/3 x = y
 
Last edited:

Pavan

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Nov 2, 2010
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2,111
If it's algebra - you're safe. That's standard basics. If it's calculus, then brush up...
 
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