One is equal to minus one.

marco

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1 = √(1)
= √[(−1).(−1)]
= √[(−1)^(2)]
= [(-1)^2)^0,5]
1 = -1

Where is my mistake?
 
What did you do in the 4th line?
= [(-1)^2)^0,5]
?
 
What did you do in the 4th line?
= [(-1)^2)^0,5]
?

-1^2 = 1 and then if memory serve ^1/2 is the square root or something so √1 = 1

So 1 = 1 and what Eks said ^
 
-1^2 = 1 and then if memory serve ^1/2 is the square root or something so √1 = 1

So 1 = 1 and what Eks said ^
Shhh
Was trying to give OP a hard time in case they just reposted this without even understanding it :X3: .
 
4th line.
Square root and squared cancel out.
(√)^2 or 1/2 X 2 =0
√(9^2) = 9
 
1 = √(1)
= √[(−1).(−1) ....-1 . -1 = + 1
= √[(−1)^(2)] .... -1 . -1 = (-1)^2
= [(-1)^2)^0,5] .... powers cancel
1 = -1
 
Correct. Sqrt(1) = Plus one or minus one.

The assertion is incorrect as you're not performing the same operations completely on both sides of the equation.
Plus the implication from the OP is that 0 = 2 or 0= -2
 
(-1 * -1) = 1 but, +1 != -1 following the rules of mathematics.
You can say that: 1 = -1 || +1
 
The calculation method is correct but:
Mathematical rules do not quite allow square roots of negative numbers.

√(−1) would be an imaginary number "i".

√(−9) would simplify to:

√(−1) . √9
= 3i
 
Last edited:
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