We can also write this as 48÷1(9+3) as we can say a missing real number in front of the brackets implies the value of 1. So 48÷(9+3) = 48÷1(9+3)=48÷11=48/11
Now you are confusing the issue by stating that 9 + 3 = 11
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We can also write this as 48÷1(9+3) as we can say a missing real number in front of the brackets implies the value of 1. So 48÷(9+3) = 48÷1(9+3)=48÷11=48/11
Nope. Brackets always comes first.
The answer is 2. In 48/2(9+3), the 2 forms part of the brackets. Adding brackets to 48/2 changes the argument entirely.
Now you are confusing the issue by stating that 9 + 3 = 11
Adding brackets to 48/2 changes the argument entirely.
Sorry, wasn't referring to the post above mine, but to all the cleverjacks insisting that it's 288he is adding brackets to explain it better, it's the same thing.
Not even by the furthest stretch of the imagination.
The answer is 2. In 48/2(9+3), the 2 forms part of the brackets. Adding brackets to 48/2 changes the argument entirely.
:wtf:
I've always assumed MyBB forumites are smart
Can't really believe this thread got so long!
288
If the ÷ was a + or - your argument would be well ..almost valid, but I'll give you that. The real sum should be
48÷ 2 x (9+3). Now following PEMDAS the answer is 288 .LEFT to RIGHT
People generaly get confused here ----> 2(
Sorry, wasn't referring to the post above mine, but to all the cleverjacks insisting that it's 288![]()
Wrong, 2(9+3) is not 2x(9+3), its (2*9+2*3)
Fine, I'll just leave this here for you guys to disprove. It's exactly the same thing as the original statement. Adding brackets because you can't visualise the equation is your own fault.
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Nope, the single statement 2(9+3) is 2*12 =24
It's the latter. You're allowed to add brackets around the entire equation, but not around individual expressions within the equation because that would change the meaning of it.It's a very ambiguous question. Its not clear if the question is (48/2)*(9+3) or (48/2(9+3)) as Mike Hoxbig has pointed out.
Once it gets written out properly it becomes very simple to solve the problem.