Hoping someone can shed some light, please:
Our alarm has two power packs (brand: Peak Power model TR6-HT_S042) each with an IDS 8Ah Gel battery in it, installed about 8 months ago. These are only used to power the external sensors (the rest is powered off the panel's own 8ah battery). Tonight they failed after 1 hour.
Instead of just replacing the batteries with the same I thought I should get bigger batteries but when I calculated the current draw to see what to get I do not understand how the current battery size isn't more than ample:
I traced which sensors are connected to which pack and looked up the manufacturer's (optex) spec for each one for current draw (@ 12VDC). I get to 58mA (1 x BX80 @ 38 mA + 1 x VXI-ST @ 20mA) on pack 1 and 77 mA (3 x VX + 1 x FIT-AT @ 17mA) on pack 2.
Since they were installed the longest outage I can remember (transformer fault) wasnt longer than 8 hours.
Even if you say 12 hours, there is no way that load would drain the batteries beyond 50% to damage them.
So now I'm stumped...
Before these packs were installed, all the external sensors were on a single pack (one of those Sherlo, assume 7Ah battery) which eventually couldn't handle the LS anymore and installer replaced with these two.
Anyone with experience with similar setup? Either the current draw actually much much higher than Optex says or these batteries or power packs are a load of rubbish.
I want to put in something that will actually last. Maybe I should switch to one of those Ratel 430m?
Thanks.